Mary passed a certain gas station on a highway while traveling west at a constant speed of 50 miles per hour. Then, 15 minutes later, Paul passed the same gas station while traveling west at a constant speed of 60 miles per hour. If both drivers maintained their speeds and both remained on the highway for at least 2 hours, how long after he passed the gas station did Paul catch up with Mary?

Answer: 1 hour 15minStep-by-step explanation:When Paul passes the gas station Mary si already 12.5 miles awayX=v t = 50mph 0.25h = 12.5 miles. (15min equals a quarter hour)From that moment to the meeting point we’ll have only one t (time) and one x (final point) for both cars For Mary we have X= Xo + v t= 12.5 miles + 50mph tFor Paul we haveX=v t = 60mph tAs x si the same in both equations 60mph t = 12.5 miles + 50mph t(60mph - 50mph) t = 12.5miles10mph t = 12.5milest = 12.5miles/10mpht = 1,25 h